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Nov 25, 2020 at 3:36 history edited Noah Snyder CC BY-SA 4.0
Putting an equation in display mode to fix a bug in how it was displaying on mobile
Jun 19, 2020 at 19:59 vote accept CommunityBot
Jun 19, 2020 at 19:59 comment added user159891 It seems very tedious to verify that this indeed defines a tensor functor. I checked one of the three diagrams and it worked out, so I'm getting confident that it works! Many thanks for the help!
Jun 19, 2020 at 19:35 comment added Noah Snyder @user745578: Yes, that's my proposal.
Jun 19, 2020 at 19:30 comment added user159891 So if I understand correctly, we have that $(G, \varphi_0 = id_I, \varphi_2)$ is a tensor functor where $id_I \in Hom_{C^{str}}(\emptyset, (I))$ and $\varphi_2(U,V):= id_{U \otimes V} \in Hom_{C^{str}}((U,V),(U \otimes V))$?
Jun 19, 2020 at 18:43 comment added user159891 Thanks! I will see if this works!
Jun 19, 2020 at 18:29 history answered Noah Snyder CC BY-SA 4.0