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Timeline for An unpublished result of H. Hamm

Current License: CC BY-SA 4.0

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Jun 15, 2020 at 12:26 comment added user2520938 @ViditNanda Thanks for your comment. In the article you mention it seems though that the singular locus of $f^{-1}(0)$ has to be compact. Now I'm really looking for a general result, so I do not think that this article really contains what I'm looking for. I will take a look at citing literature though, thanks.
Jun 15, 2020 at 11:48 comment added Vidit Nanda Note that sets like $\{|f(x)| < p\}$ are equivalent to $\{|f(x)|^2 < p^2\}$ and the norm-squared function is much friendlier to work with (eg it is smooth). I don't know if your desired result has appeared anywhere, but I think a good starting point is Durfee's paper (jstor.org/stable/1999065). This does what you want globally, ie., without the $\{|x|<R\}$ part; to make the equivalence local, you have to show that the gradient vector field of $-|f|^2$ points inwards along the boundary $\{|x|=R\} - \{f=0\}$.
Jun 15, 2020 at 10:57 history edited user2520938 CC BY-SA 4.0
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Jun 15, 2020 at 10:44 history asked user2520938 CC BY-SA 4.0