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Jun 14, 2020 at 17:58 comment added Alexander Chervov For n=2, and difference, not sum - see some remarks here: math.stackexchange.com/questions/146259/… may be @David E Speyer argument can be modified..
S Jun 14, 2020 at 17:50 history suggested Victor G CC BY-SA 4.0
clarification
Jun 14, 2020 at 17:30 comment added HenrikRüping For $n=2$ I got the eigenvalues $0,0,\pm \sqrt{2(a^2+b^2)}$ in your example.
Jun 14, 2020 at 17:27 review Suggested edits
S Jun 14, 2020 at 17:50
Jun 14, 2020 at 16:46 review First posts
Jun 14, 2020 at 19:57
Jun 14, 2020 at 16:37 history asked Victor G CC BY-SA 4.0