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Idempotent complete category wichwhich is not abelian

In the following, we work with additive categories.

We say that a category is weakly idempotent complete if all the epimorphisms wichwhich admit a section have kernel. It's equivalent to the dual statement  : all the monomorphisms wichwhich admit a retract have cokernel.

A stronger notion is the notion of idempotent complete. A category is idempotent complete if each morphism in $f:A \rightarrow A | f²=f$$\{f:A \rightarrow A \;|\; f^2=f\}$ has a kernel or equivalentelyequivalently a cokernel. As suggestssuggested by the name of these notions, an idempotenteidempotent complete category is weakly idempotent.

We know that an abelian category is idempotent complete.

We have the following examples :

• We consider the category $K_{vect} ^{ ^{\ge n}}$ of vector spaces over a field $K$ with no non-nul vertorvector space of smaller dimension than $n$. Then $K_{vect} ^{\ge n}$ is not weakly idempotent complete since the trivial projection $K^{n+1} \twoheadrightarrow K^n$ has a section but no kernel.

• We consider the category $K_{vect} ^ {^{\equiv 0 [2]}}$ of vector spaces over a field $K$ with pair dimension or infinite dimension. Then $K_{vect} ^ {^{\equiv 0 [2]}}$ is weakly idempotent complete. But it's not idempotent compltecomplete since the projector $K^{2} \stackrel{\begin{pmatrix}Id & 0 \\ 0 & 0\end{pmatrix}}{\rightarrow} K^2$ has no kernel or cokernel.

So this is the question :

Is somenonesomeone knows an example of an idempotent complete category wichwhich is not abelian  ?

(here we don't need to have the Grothendieck's axioms)

Thanks you, Timothée

Idempotent complete category wich is not abelian

In the following, we work with additive categories.

We say that a category is weakly idempotent complete if all the epimorphisms wich admit a section have kernel. It's equivalent to the dual statement  : all the monomorphisms wich admit a retract have cokernel.

A stronger notion is the notion of idempotent complete. A category is idempotent complete if each morphism $f:A \rightarrow A | f²=f$ has a kernel or equivalentely a cokernel. As suggests by the name of these notions, an idempotente complete category is weakly idempotent.

We know that an abelian category is idempotent complete.

We have the following examples :

• We consider the category $K_{vect} ^{ ^{\ge n}}$ of vector spaces over a field $K$ with no non-nul vertor space of smaller dimension than $n$. Then $K_{vect} ^{\ge n}$ is not weakly idempotent complete since the trivial projection $K^{n+1} \twoheadrightarrow K^n$ has a section but no kernel.

• We consider the category $K_{vect} ^ {^{\equiv 0 [2]}}$ of vector spaces over a field $K$ with pair dimension or infinite dimension. Then $K_{vect} ^ {^{\equiv 0 [2]}}$ is weakly idempotent complete. But it's not idempotent complte since the projector $K^{2} \stackrel{\begin{pmatrix}Id & 0 \\ 0 & 0\end{pmatrix}}{\rightarrow} K^2$ has no kernel or cokernel.

So this is the question :

Is somenone knows an example of an idempotent complete category wich is not abelian  ?

(here we don't need to have the Grothendieck's axioms)

Thanks you, Timothée

Idempotent complete category which is not abelian

In the following, we work with additive categories.

We say that a category is weakly idempotent complete if all the epimorphisms which admit a section have kernel. It's equivalent to the dual statement: all the monomorphisms which admit a retract have cokernel.

A stronger notion is the notion of idempotent complete. A category is idempotent complete if each morphism in $\{f:A \rightarrow A \;|\; f^2=f\}$ has a kernel or equivalently a cokernel. As suggested by the name of these notions, an idempotent complete category is weakly idempotent.

We know that an abelian category is idempotent complete.

We have the following examples :

• We consider the category $K_{vect} ^{ ^{\ge n}}$ of vector spaces over a field $K$ with no non-nul vector space of smaller dimension than $n$. Then $K_{vect} ^{\ge n}$ is not weakly idempotent complete since the trivial projection $K^{n+1} \twoheadrightarrow K^n$ has a section but no kernel.

• We consider the category $K_{vect} ^ {^{\equiv 0 [2]}}$ of vector spaces over a field $K$ with pair dimension or infinite dimension. Then $K_{vect} ^ {^{\equiv 0 [2]}}$ is weakly idempotent complete. But it's not idempotent complete since the projector $K^{2} \stackrel{\begin{pmatrix}Id & 0 \\ 0 & 0\end{pmatrix}}{\rightarrow} K^2$ has no kernel or cokernel.

So this is the question :

Is someone knows an example of an idempotent complete category which is not abelian?

(here we don't need to have Grothendieck's axioms)

Thanks you, Timothée

Source Link

Idempotent complete category wich is not abelian

In the following, we work with additive categories.

We say that a category is weakly idempotent complete if all the epimorphisms wich admit a section have kernel. It's equivalent to the dual statement : all the monomorphisms wich admit a retract have cokernel.

A stronger notion is the notion of idempotent complete. A category is idempotent complete if each morphism $f:A \rightarrow A | f²=f$ has a kernel or equivalentely a cokernel. As suggests by the name of these notions, an idempotente complete category is weakly idempotent.

We know that an abelian category is idempotent complete.

We have the following examples :

• We consider the category $K_{vect} ^{ ^{\ge n}}$ of vector spaces over a field $K$ with no non-nul vertor space of smaller dimension than $n$. Then $K_{vect} ^{\ge n}$ is not weakly idempotent complete since the trivial projection $K^{n+1} \twoheadrightarrow K^n$ has a section but no kernel.

• We consider the category $K_{vect} ^ {^{\equiv 0 [2]}}$ of vector spaces over a field $K$ with pair dimension or infinite dimension. Then $K_{vect} ^ {^{\equiv 0 [2]}}$ is weakly idempotent complete. But it's not idempotent complte since the projector $K^{2} \stackrel{\begin{pmatrix}Id & 0 \\ 0 & 0\end{pmatrix}}{\rightarrow} K^2$ has no kernel or cokernel.

So this is the question :

Is somenone knows an example of an idempotent complete category wich is not abelian ?

(here we don't need to have the Grothendieck's axioms)

Thanks you, Timothée