Timeline for Is there a condensation from $\aleph_1^{\aleph_0}$ onto a metrizable compact space?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 14, 2020 at 4:51 | vote | accept | Alexander Osipov | ||
| Jun 14, 2020 at 4:50 | vote | accept | Alexander Osipov | ||
| Jun 14, 2020 at 4:51 | |||||
| Jun 14, 2020 at 4:50 | vote | accept | Alexander Osipov | ||
| Jun 14, 2020 at 4:50 | |||||
| Jun 14, 2020 at 4:50 | vote | accept | Alexander Osipov | ||
| Jun 14, 2020 at 4:50 | |||||
| Jun 13, 2020 at 22:39 | answer | added | Will Brian | timeline score: 11 | |
| Jun 13, 2020 at 20:15 | answer | added | Taras Banakh | timeline score: 9 | |
| Jun 13, 2020 at 14:32 | history | edited | YCor | CC BY-SA 4.0 |
edited tags
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| Jun 13, 2020 at 13:03 | comment | added | Alexander Osipov | $N$ is a space of natural numbers. We can assume that $N^N$ is a space of irrational numbers. Sierpinski proved that irrational numbers admits a condensation onto [0,1]. | |
| Jun 13, 2020 at 12:48 | comment | added | YCor | What's $N$? also, is it implicit that there exists a condensation of $\aleph_0^{\aleph_0}$ onto a metrizable compact space? | |
| Jun 13, 2020 at 12:12 | comment | added | Alexander Osipov | Strengthening the question. Is there a condensation from $D^{\aleph_0}$ onto $N^N$? | |
| Jun 13, 2020 at 11:53 | history | asked | Alexander Osipov | CC BY-SA 4.0 |