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Jun 12, 2020 at 20:47 vote accept user158968
Jun 12, 2020 at 15:17 answer added ofer zeitouni timeline score: 1
Jun 11, 2020 at 16:07 comment added S.Surace Sure, this makes sense. Unfortunately I don't know an answer to this. The exponential martingales and the sum don't seem to go well together.
Jun 11, 2020 at 15:35 comment added user158968 @S.Surace Any measure that is absolutely continuous wrt Wiener measure is a Girsanov measure and corresponds to a $W^{1,2}$ drift.
Jun 11, 2020 at 15:25 comment added user158968 @S.Surace Because it has a density.
Jun 11, 2020 at 15:09 comment added S.Surace It is not clear to me why the convex combination of a Girsanov measure should be a Girsanov measure. Where do you get this from?
Jun 11, 2020 at 3:54 history edited user158968 CC BY-SA 4.0
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Jun 11, 2020 at 1:35 history edited user158968 CC BY-SA 4.0
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Jun 10, 2020 at 21:23 history asked user158968 CC BY-SA 4.0