Timeline for Dense linear span implies closed convex hull has non-empty interior
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Jun 9, 2020 at 15:45 | comment | added | Nate Eldredge | @Zorn'sLama: Your previous comment is just saying something trivial: if $\operatorname{co}(Y)$ is dense in the ball then its closure contains the ball, so of course the interior of the closure is nonempty. | |
| Jun 9, 2020 at 15:35 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
added 476 characters in body
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| Jun 9, 2020 at 15:25 | comment | added | ABIM | ok, fantastic, then my theorem still holds ;) Thanks Iosif! (Had a small hard palpatation when I tried to extend if naively I see). | |
| Jun 9, 2020 at 15:25 | comment | added | Iosif Pinelis | @Zorn'sLama : Concerning your last comment: yes, of course. | |
| Jun 9, 2020 at 15:23 | comment | added | ABIM | If for example, $co(Y)$ is dense in $Ball(0,1)$ in $X$, then everything should work no? | |
| Jun 9, 2020 at 15:22 | comment | added | Iosif Pinelis | @Zorn'sLama : I suspect $X$ would have to be finite dimensional for this to hold for all $Y$, but don't know at the moment whether this is true. | |
| Jun 9, 2020 at 15:21 | comment | added | ABIM | what would be a reasonable condition on $Y$ (or $X$ for that matter) such that this doesn't happen? | |
| Jun 9, 2020 at 15:19 | vote | accept | ABIM | ||
| Jun 9, 2020 at 15:16 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |