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Timeline for 3D similarities and quaternions?

Current License: CC BY-SA 4.0

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Sep 20, 2020 at 6:53 history edited YCor
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Jun 8, 2020 at 15:04 vote accept Goulifet
Jun 8, 2020 at 9:45 answer added wlad timeline score: 3
Jun 8, 2020 at 9:21 comment added wlad @BertramArnold Shouldn't that be $(a,b,x)\circ v = avb + x$
Jun 8, 2020 at 9:09 comment added wlad In terms of matrices, the group of similarity transformations is a subgroup of the group of affine transformations, the latter of which has a matrix representation
Jun 8, 2020 at 9:05 comment added Bertram Arnold In dimension $4$, any orthogonal transformation is of the form $v\mapsto a\cdot v\cdot b$ with $a,b\in \mathbb S^3\subset H^\times$. This defines the double covering $SU(2)\times SU(2)\to SO(4)$. This generalizes immediately to similarities, the group of which is $\mathbb (H^\times \mathbb H^\times / \big((\lambda,1)\sim (1,\lambda)\big)\ltimes \mathbb H$ acting by $(a,b,x)\circ v = avb + v$. To get to $SO(3)$, restrict to those transformations preserving $\mathbb R^\perp\subset \mathbb H$, which is equivalent to $x\in \mathbb R^\perp,ab\in\mathbb R$, i.e. $b$ is proportional to $\overline a$.
Jun 8, 2020 at 9:04 comment added wlad What about $v \mapsto qvq^* + u$ where $v$ is a vector quaternion, $u$ is a vector quaternion, and $q$ is a quaternion
Jun 8, 2020 at 8:16 history edited YCor CC BY-SA 4.0
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Jun 8, 2020 at 2:22 comment added Theo Johnson-Freyd This question is, more or less, what led Hamilton to discover the quaternions in the first place.
Jun 8, 2020 at 1:46 comment added Steven Stadnicki One problem is that the rotation action of the quaternions isn't given by $q\mapsto(f_q(z): z\mapsto qz)$ as it is with complex numbers representing 2d rotations, but rather $q\mapsto(f_q(z): z\mapsto q^{-1}zq)$ (possibly with the specific conjugation inverted depending on your conventions).
Jun 8, 2020 at 1:27 history asked Goulifet CC BY-SA 4.0