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Jun 14, 2020 at 3:04 review Reopen votes
Jun 15, 2020 at 20:11
Jun 8, 2020 at 8:35 comment added YCor The second "question" was answered in a more general setting in the comments of this subsequent question where the exercise-style was not followed and that question was well-received. This makes it a duplicate, but rather than closing on this grounds, one could remove the second question and focus on the 1st one. But at the same time the first question is possibly too easy to deserve a separate question (it's claimed as easy in the linked question).
Jun 8, 2020 at 8:30 history edited YCor CC BY-SA 4.0
corrected tag; fixed misuse of mapsto
Jun 8, 2020 at 6:16 comment added András Bátkai Such questions are closed, though I was not involved, because there is no question. It sounds like a (hard) exercise for extra credits.
Jun 8, 2020 at 4:03 review Reopen votes
Jun 8, 2020 at 12:38
Jun 8, 2020 at 3:47 comment added abx I am probably missing something, but why was the question closed? Is there an obvious answer to the second question?
Jun 7, 2020 at 20:58 history closed Ben McKay
Jochen Glueck
Loïc Teyssier
user44191
Michael Greinecker
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S Jun 7, 2020 at 20:41 history edited leo monsaingeon
This problem is of purely settheoretic neature
S Jun 7, 2020 at 20:41 history suggested Dieter Kadelka
This problem is of purely settheoretic neature
Jun 7, 2020 at 11:45 comment added Dieter Kadelka One should note that the problems are of purely settheoretic nature. In the first question $\mathbb{Q}$ can be replaced by $\mathbb{N}_0$ and then $g(x) := \max_{y,z \in \mathbb{N_0} :y+z \leq 2x} |f(x,y)|$ (of course very crude) does the job. For the second question I think $\mathbb{R}$ should be well ordered and then ?
Jun 7, 2020 at 11:41 review Suggested edits
S Jun 7, 2020 at 20:41
Jun 7, 2020 at 8:58 review Close votes
Jun 7, 2020 at 21:02
Jun 7, 2020 at 8:33 history asked Gintoki-Sakata CC BY-SA 4.0