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Jun 6, 2020 at 4:23 vote accept Karim KHAN
Jun 6, 2020 at 4:22 comment added Nate Eldredge @KarimKHAN: The subsequence $y_{n_k}$ in my answer isn't necessarily convergent, though it would be possible to find a further subsequence of it which is.
Jun 6, 2020 at 4:20 comment added Karim KHAN If $ \{y_n \} $ is relatively weakly compact, then $ \{y_ {n_k} \} $ is a convergent sequence?
Jun 6, 2020 at 4:14 history answered Nate Eldredge CC BY-SA 4.0