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Jun 5, 2020 at 17:37 history became hot network question
Jun 5, 2020 at 15:45 comment added Moishe Kohan The right statement is: Suppose that $(M,g)$ does not split locally as Riemannian product. Then the LC connection determines the metric up to a constant factor.
Jun 5, 2020 at 13:42 comment added Student From the metric we can derive several quantities (eg. curvature tensor). A question I'd like to ask is: which derived quantities determine the metric?
Jun 5, 2020 at 13:31 answer added Sebastian timeline score: 5
Jun 5, 2020 at 12:05 vote accept formercannibal
Jun 5, 2020 at 11:42 answer added Liviu Nicolaescu timeline score: 13
Jun 5, 2020 at 9:42 review First posts
Jun 5, 2020 at 11:22
Jun 5, 2020 at 9:39 answer added Ben McKay timeline score: 17
Jun 5, 2020 at 9:37 history asked formercannibal CC BY-SA 4.0