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In $R^3$, since the spheres are concentric, not only all faces are regular, but also all edges are of the same length, and all faces are inscribed in circles of the same radius, hence are congruent. Also, all dihedral angles between faces with a common edge are equal, which makesimplies that all vertices equivalentare of the same valence. This implies thatmakes the polytope is regular. It seems that this reasoning can be generalized to all dimensions.

In $R^3$, since the spheres are concentric, not only all faces are regular, but also all edges are of the same length, and all faces are inscribed in circles of the same radius, hence are congruent. Also, all dihedral angles between faces with a common edge are equal, which makes all vertices equivalent. This implies that the polytope is regular. It seems that this reasoning can be generalized to all dimensions.

In $R^3$, since the spheres are concentric, not only all faces are regular, but also all edges are of the same length, and all faces are inscribed in circles of the same radius, hence are congruent. Also, all dihedral angles between faces with a common edge are equal, which implies that all vertices are of the same valence. This makes the polytope regular. It seems that this reasoning can be generalized to all dimensions.

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In $R^3$, since the spheres are concentric, not only all faces are regular, but also all edges are of the same length, and all faces are inscribed in circles of the same radius, hence are congruent. Also, all dihedral angles between faces with a common edge are equal, which makes all vertices equi-valentequivalent. This implies that the polytope is regular. It seems that this reasoning can be generalized to all dimensions.

In $R^3$, since the spheres are concentric, not only all faces are regular, but also all edges are of the same length, and all faces are inscribed in circles of the same radius, hence are congruent. Also, all dihedral angles between faces with a common edge are equal, which makes all vertices equi-valent. This implies that the polytope is regular. It seems that this reasoning can be generalized to all dimensions.

In $R^3$, since the spheres are concentric, not only all faces are regular, but also all edges are of the same length, and all faces are inscribed in circles of the same radius, hence are congruent. Also, all dihedral angles between faces with a common edge are equal, which makes all vertices equivalent. This implies that the polytope is regular. It seems that this reasoning can be generalized to all dimensions.

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In $R^3$, since the spheres are concentric, not only all faces are regular, but also all edges are of the same length, and all faces are inscribed in circles of the same radius, hence are congruent. Also, all dihedral angles between faces with a common edge are equal, which makes every vertexall vertices equi-valent. This implies that the polytope is regular. It seems that this reasoning can be generalized to all dimensions.

In $R^3$, since the spheres are concentric, not only all faces are regular, but also all edges are of the same length, and all faces are inscribed in circles of the same radius, hence are congruent. Also, all dihedral angles between faces with a common edge are equal, which makes every vertex equi-valent. This implies that the polytope is regular. It seems that this reasoning can be generalized to all dimensions.

In $R^3$, since the spheres are concentric, not only all faces are regular, but also all edges are of the same length, and all faces are inscribed in circles of the same radius, hence are congruent. Also, all dihedral angles between faces with a common edge are equal, which makes all vertices equi-valent. This implies that the polytope is regular. It seems that this reasoning can be generalized to all dimensions.

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