Timeline for Is every generator of $Z({\rm Spin}_n^{\epsilon}(q))$ a square element in ${\rm Spin}_n^{\epsilon}(q)$?
Current License: CC BY-SA 4.0
3 events
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| Jun 3, 2020 at 7:29 | comment | added | Derek Holt | Yes, you seem to have just repeated what I said in my answer. | |
| Jun 3, 2020 at 3:58 | comment | added | Yi Wang | Thanks a lot! Is what you mean when $Z({\rm Spin}_n^\epsilon(q))\cong C_4$, then, for question A, all geneartors of order 4 are not squares, and all generators of order 2 are yes, and for question $B$, the answer is also negative; when $Z({\rm Spin}_n^\epsilon(q))\cong C_2\times C_2$, then for question A, all generators of order 2 are squares, and for question B, the answer is also yes? | |
| Jun 1, 2020 at 14:39 | history | answered | Derek Holt | CC BY-SA 4.0 |