Timeline for Asymptotics of sum involving Stirling numbers
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 2, 2020 at 1:03 | vote | accept | David Galvin | ||
| Jun 1, 2020 at 17:45 | answer | added | skbmoore | timeline score: 5 | |
| Jun 1, 2020 at 1:34 | comment | added | David Galvin | @RichardStanley I have corrected the sum --- the power of $\beta$ should have been $j$ rather than $n$. | |
| Jun 1, 2020 at 1:33 | history | edited | David Galvin | CC BY-SA 4.0 |
Corrected typo in summation --- power of $\beta$ should have been $j$, not $n$.
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| Jun 1, 2020 at 0:30 | comment | added | Richard Stanley | The factor $\beta^n$ seems superfluous. | |
| May 31, 2020 at 20:49 | comment | added | David Galvin | Yes, my sum has a falling rather than a rising power. But as observed in a comment in the earlier question, when the argument of the Pochhammer symbol is constant (not depending on n), there's not any difference in difficulty between falling and rising power. | |
| May 31, 2020 at 20:39 | comment | added | Carlo Beenakker | your earlier question had a rising factorial (Pochhammer) instead of a falling factorial, is that intentional? | |
| May 31, 2020 at 17:37 | history | asked | David Galvin | CC BY-SA 4.0 |