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M. Winter
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The answer to your first question is No.

Consider the 5x5 square as a lattice polytope in two different ways as seen above. Each tiling of one of these sqares gives a tiling of the other. But you can choose the tiles in such a way, so that they are lattice polytope in only one of the squares.

So the right square is tiled with quasi-lattice polytopes (as seen in the left square) that are not lattice polytopes.

The answer to your first question is No.

Consider the 5x5 square as a lattice polytope in two different ways as seen above. Each tiling of one of these sqares gives a tiling of the other. But you can choose the tiles in such a way, so that they are lattice polytope in only one of the squares.

So the right square is tiled with quasi-lattice polytopes (as seen in the left square) that are not lattice polytopes.

The answer to your first question is No.

Consider the 5x5 square as a lattice polytope in two different ways as seen above. Each tiling of one of these sqares gives a tiling of the other. But you can choose the tiles in such a way, so that they are lattice polytope in only one of the squares.

So the right square is tiled with quasi-lattice polytopes that are not lattice polytopes.

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M. Winter
  • 13.6k
  • 3
  • 28
  • 70

The answer to your first question is No.

Consider the 5x5 square as a lattice polytope in two different ways as seen above. Each tiling of one of these sqares gives a tiling of the other. But you can choose the tiles in such a way, so that they are lattice polytope in only one of the squares (as demonstrated by the gray tile).

So the right square is tiled with quasi-lattice polytopes (as seen in the left square) that are not lattice polytopes.

The answer to your first question is No.

Consider the 5x5 square as a lattice polytope in two different ways as seen above. Each tiling of one of these sqares gives a tiling of the other. But you can choose the tiles in such a way, so that they are lattice polytope in only one of the squares (as demonstrated by the gray tile).

So the right square is tiled with quasi-lattice polytopes that are not lattice polytopes.

The answer to your first question is No.

Consider the 5x5 square as a lattice polytope in two different ways as seen above. Each tiling of one of these sqares gives a tiling of the other. But you can choose the tiles in such a way, so that they are lattice polytope in only one of the squares.

So the right square is tiled with quasi-lattice polytopes (as seen in the left square) that are not lattice polytopes.

Source Link
M. Winter
  • 13.6k
  • 3
  • 28
  • 70

The answer to your first question is No.

Consider the 5x5 square as a lattice polytope in two different ways as seen above. Each tiling of one of these sqares gives a tiling of the other. But you can choose the tiles in such a way, so that they are lattice polytope in only one of the squares (as demonstrated by the gray tile).

So the right square is tiled with quasi-lattice polytopes that are not lattice polytopes.