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Jun 2, 2020 at 13:25 vote accept KKD
May 29, 2020 at 22:05 answer added Vít Tuček timeline score: 1
May 29, 2020 at 21:21 comment added KKD Thanks for your fast answer but I cannot follow you. I'm still learning all these things. By space of highest weight vectors you mean $N$ has a basis of highest weight vectors? Why? And why is $M$ covered by Verma Modules?
May 29, 2020 at 14:51 comment added Vít Tuček I am familiar only with complex numbers, but there the result is easy, because being $B$-invariant means that it is a space of highest weight vectors and then your $M$ is covered by Verma modules.
May 29, 2020 at 14:40 history edited YCor
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May 29, 2020 at 14:27 history asked KKD CC BY-SA 4.0