Skip to main content
9 events
when toggle format what by license comment
May 28, 2020 at 18:20 history edited Jason Zhao CC BY-SA 4.0
typo, $f_i$ should be $f$
May 28, 2020 at 18:20 comment added Jason Zhao @AndrejBauer yes, thanks for catching the typo
May 28, 2020 at 6:44 comment added Jochen Glueck It might be worthwhile to note that the very definition of a Banach space - i.e., completeness - can be phrased in terms of a quantifier swap: A metric space $(M,d)$ is complete if and only if, for every sequence $(x_n)$ in $M$, the following two assertions are equivalent: $\exists x \in M \; \forall \varepsilon > 0 \; \exists n_0 \; \forall n \ge n_0: \; d(x_n,x) < \varepsilon$, and $\forall \varepsilon > 0 \; \exists x \in M \; \exists n_0 \; \forall n \ge n_0: \; d(x_n,x) < \varepsilon$. (Since the second assertion is equivalent to $(x_n)$ being a Cauchy sequence.)
May 28, 2020 at 6:17 comment added Andrej Bauer Should the last $f_i$ in the displayed formula be $f$?
May 28, 2020 at 6:15 comment added Andrej Bauer See my answer to "Techniques for reversing the order of quantifiers". While you're reading it I'll try to see if your example is also about compactness.
May 27, 2020 at 21:07 comment added Cameron Zwarich Is there a logical interpretation of other quantifier swaps in analysis, e.g. any of the more basic compactness arguments?
May 27, 2020 at 20:14 comment added Robert Israel Swapping quantifiers depends a lot on the statement that comes after the quantifiers, and not just on the Banach space. Even in a finite set, $\forall x \exists y \; A(x,y)$ may or may not be equivalent to $\exists y \forall x \; A(x,y)$, depending on $A$.
May 27, 2020 at 17:50 review First posts
May 27, 2020 at 18:20
May 27, 2020 at 17:45 history asked Jason Zhao CC BY-SA 4.0