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Jun 2, 2020 at 16:23 vote accept santker heboln
May 24, 2020 at 23:28 history became hot network question
May 24, 2020 at 17:42 answer added Jochen Wengenroth timeline score: 5
May 24, 2020 at 17:34 answer added M.González timeline score: 7
May 24, 2020 at 17:24 answer added Yemon Choi timeline score: 8
May 24, 2020 at 17:09 comment added santker heboln I mean the first, i.e. $f_1$ has closed range. In that sense what I mean by "topological exactness" is algebraic exactness.
May 24, 2020 at 16:51 comment added Yemon Choi Just to get the terminology straight in my head: by topologically short exact do you mean the morphisms are bounded linear maps but you have short exactness in the category of vector spaces and linear maps? In other words, $f_1$ has closed range, and not just "$f_1(X_1)$ is dense in $\ker(f_2)$"?
May 24, 2020 at 15:48 history edited YCor
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May 24, 2020 at 15:28 history asked santker heboln CC BY-SA 4.0