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Jul 21, 2020 at 8:28 vote accept M. Winter
Jul 20, 2020 at 22:21 vote accept M. Winter
Jul 20, 2020 at 22:49
May 23, 2020 at 17:17 history edited Dmitri Panov CC BY-SA 4.0
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May 23, 2020 at 17:13 comment added Dmitri Panov I added a reference. Yes, starting with such a polytope you get a tiling of $\mathbb H^4$, in the same way as cubes tile $\mathbb R^n$. And what I say is that you need to take the union of two tiles that share a common hyperface to get a new polytope as you want. This can be continued as far as you want.
May 23, 2020 at 17:11 history edited Dmitri Panov CC BY-SA 4.0
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May 23, 2020 at 17:06 comment added M. Winter Thank you for your answer. I am not familiar with some terminology: 1. what is this "regular compact right-angled 120-cell" in hyperbolic 4-space. Is it like a tiling of 4-space? I wasn't able to find out what a "convex hyperbolic polytope" is via google. 2. What does it mean to "double it on one face"?
May 23, 2020 at 16:54 history answered Dmitri Panov CC BY-SA 4.0