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May 29, 2020 at 13:38 vote accept Henning
May 24, 2020 at 21:30 comment added Mateusz Kwaśnicki The Fourier transform of $x$ is indeed $i \delta_0'$, and more generally, the Fourier transform of a polynomial $P(x)$ is $P(-i\partial_x) \delta_0$. I am not sure I have a good reference; Vladimirov's Methods of the Theory of Generalized Functions is one of the standard references, I think.
May 24, 2020 at 17:06 comment added Henning Thank you! Since I am not trained and experienced in distribution theory (and Fourier transforms of distributions), I cannot see that the Fourier transform of $f(x)=x$ for $x \in \mathbb{R},$ that is, essentially $\delta'$ (correct?) is supported in $\{0\}.$ What is the difference to polynomials of higher order? Do you know any good reference for these basics?
May 23, 2020 at 15:49 history edited Mateusz Kwaśnicki CC BY-SA 4.0
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May 23, 2020 at 15:42 history answered Mateusz Kwaśnicki CC BY-SA 4.0