Timeline for Is the Singer cycle preserved by field automorphisms and graph automorphisms?
Current License: CC BY-SA 4.0
9 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
May 25, 2020 at 9:13 | vote | accept | Groups | ||
May 25, 2020 at 8:54 | answer | added | Derek Holt | timeline score: 1 | |
May 25, 2020 at 8:27 | comment | added | Groups | @DerekHolt I can now see that a field automorphism normalises $\langle x\rangle$ by Anton's comment. But how about the graph automorphism (even though the answer seems to be yes)? | |
May 25, 2020 at 7:44 | comment | added | Derek Holt | So the answer to the question is yes, this maximal subgroup extends to a maximal subgroup of ${\rm Aut}(T)$. | |
May 25, 2020 at 6:32 | history | edited | Groups | CC BY-SA 4.0 |
deleted 3 characters in body
|
May 25, 2020 at 6:07 | comment | added | Anton B | For other questions see "The subgroup Structure of the Finite Classical Group" by P. Kleidman and M. Liebeck, it looks like $\S 4.3$ has some answers. Equation (4.3.8) shows that there is a field automorphism of $T$ normalising $\langle x \rangle$. | |
May 25, 2020 at 6:01 | comment | added | Anton B | There is no uniform shape for $x$. But there is the way to construct it in a particular situation (for given $n$ and $q$), see M. W. Short, "The primitive soluble permutation groups of degree less than 256," page 15. But it is going to be the matrix in not the same basis in which the matrix of $\sigma$ is a permutational matrix most probably. | |
May 22, 2020 at 5:49 | history | edited | Groups | CC BY-SA 4.0 |
edited title
|
May 22, 2020 at 5:35 | history | asked | Groups | CC BY-SA 4.0 |