Timeline for Finding a connection between two types of convergence
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| May 21, 2020 at 19:49 | comment | added | Iosif Pinelis | @IvanPetrov : Oops! I did not notice that you require the boundedness condition. With it, the result remains the same, but the proof gets quite a bit complicated by a straightforward but nasty truncation argument. | |
| May 21, 2020 at 19:46 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| May 21, 2020 at 19:40 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| May 21, 2020 at 14:39 | comment | added | Ivan Petrov | Yes, but the function $f$ should be bounded (from the conditions of strong-Lipschitz convergence. But as I realise, $f(x) = x$ isn't bounded. | |
| May 21, 2020 at 13:22 | comment | added | Iosif Pinelis | @IvanPetrov : The condition $f(x)\equiv x$ means $f(x)=x$ for all $x$, that is, $f$ is the identity function. It does meet your conditions on $f$, because the identity function is obviously Lipschitz. | |
| May 21, 2020 at 9:26 | comment | added | Ivan Petrov | Sorry, but can you explain please why we can use $f(x)\equiv x$? Does it meet the conditions for function $f$? | |
| May 20, 2020 at 18:29 | comment | added | Ivan Petrov | Thank you! It was very helpful! | |
| May 20, 2020 at 14:52 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |