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May 18, 2020 at 17:05 history edited Mikhail Borovoi CC BY-SA 4.0
Typo in a formula corrected
May 18, 2020 at 12:38 vote accept Mikhail Borovoi
May 18, 2020 at 12:38 comment added Mikhail Borovoi Many thanks indeed!
May 18, 2020 at 12:32 comment added Derek Holt Sorry, that was a typo. I have given an example of an element from the second class.
May 18, 2020 at 12:32 history edited Derek Holt CC BY-SA 4.0
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May 18, 2020 at 12:26 comment added Mikhail Borovoi ``$G_-$ is not a group.'' Good! However, you write: " We can take $H={\rm Sp}(4,3)$ to be the group $\{ A \in {\rm GL}(4,3) \mid AFA^{\mathsf T} = -F\}$". I was a bit puzzled....
May 18, 2020 at 12:19 comment added Mikhail Borovoi Concerning Question 2: Of course you are right! I used bad notation. By ${\rm PSp}_4(\Bbb F_3)$ I meant ${\rm PCSp}(4,3)$.
May 18, 2020 at 12:18 comment added Derek Holt $G_-$ is not a group. It is a coset of $G_+ = {\rm Sp}(4,3)$ in the larger group ${\rm CSp}(4,3)$.
May 18, 2020 at 11:51 comment added Mikhail Borovoi Concerning Question 3. You mention two conjugacy classes of involutary outer automorphisms of $H$, one of which is induces by the matrix $C$. What is the second conjugacy class?
May 18, 2020 at 11:47 comment added Mikhail Borovoi Many thanks! A stupid question: I know the definition of the symplectic group ${\rm Sp}(4,3):={\rm Sp}_4( {\Bbb F}_3)$ as the group $$G_+=\{ A \in {\rm GL}(4,3) \mid AFA^{\mathsf T} = F\}.$$ However, you take the group $$G_-=\{ A \in {\rm GL}(4,3) \mid AFA^{\mathsf T} = -F\}.$$ How can one define an isomorphism between $G_+$ and $G_-$?
May 18, 2020 at 8:49 history edited Derek Holt CC BY-SA 4.0
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May 18, 2020 at 8:32 history edited Derek Holt CC BY-SA 4.0
added 399 characters in body
May 18, 2020 at 8:02 comment added Derek Holt @LSpice Thanks! "..e looking for".
May 18, 2020 at 8:02 history edited Derek Holt CC BY-SA 4.0
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May 18, 2020 at 7:46 history answered Derek Holt CC BY-SA 4.0