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Oct 17, 2020 at 16:38 comment added Christian Chapman Purely out of curiosity where did you find this set $V_{sum}$?
Oct 17, 2020 at 7:15 comment added YCor The "surface of the unit ball" is usually called the "unit sphere".
Oct 17, 2020 at 5:03 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jun 19, 2020 at 7:02 comment added M. Winter It is hard to say anything useful for general $S$. Are you looking for a feasible algorithm to compute such an upper bounds (or exact value) or do you have some restrictions on the $S$. In full generality, $|S|$ could be ${v,-v}$ and the maximal isolation is 2. Maybe one can say more if we lower bound $|S|$, but because there are many ways to duplicate vectors this will be probably not too helpful.
Jun 19, 2020 at 5:00 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
May 20, 2020 at 5:29 comment added Pedro Juan Soto What is the motivation behind asking this question? Is there a specific application you have in mind?
May 20, 2020 at 4:16 answer added Pedro Juan Soto timeline score: 2
May 17, 2020 at 8:08 history edited YCor CC BY-SA 4.0
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May 17, 2020 at 8:07 comment added usercsw @domotorp, there would be some $\varepsilon$ such that any vector on the surface of the $d$-dimensional unit ball is at a distance at most $\varepsilon$ from one of the vectors in $V_{\text{sum}}$ right? That's the reason I am calling it an $\varepsilon$-net.
May 17, 2020 at 6:35 history edited usercsw CC BY-SA 4.0
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May 16, 2020 at 8:13 history edited usercsw CC BY-SA 4.0
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May 16, 2020 at 7:46 history edited YCor CC BY-SA 4.0
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May 16, 2020 at 7:16 history edited Wlod AA CC BY-SA 4.0
isolation
May 16, 2020 at 6:05 history asked usercsw CC BY-SA 4.0