Timeline for Solution for $Xa + X^Tb = c$ where $X^TX = I$?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Apr 20, 2021 at 15:22 | history | edited | Martin Sleziak | CC BY-SA 4.0 |
MathJax: \|
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| May 15, 2020 at 15:52 | history | edited | DSM | CC BY-SA 4.0 |
deleted 710 characters in body
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| May 15, 2020 at 15:42 | comment | added | DSM | Yikes! Thanks for that. My bad. Will think about getting around it. | |
| May 15, 2020 at 15:06 | comment | added | Aaron | Note that $(Xa)^T(X^Tb)\neq a^Tb$.You don't end up with $X^TX$, you get $(X^T)^2$. | |
| May 15, 2020 at 10:06 | history | answered | DSM | CC BY-SA 4.0 |