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May 23, 2020 at 21:46 comment added Alan @NikWeaver so we cannot have a measure theory with $\infty \cdot 0 = \infty$? I don't see how do you preclude it?
May 13, 2020 at 3:02 comment added Nik Weaver @NateEldredge right, exactly.
May 13, 2020 at 2:51 comment added Nate Eldredge Another way to say it is that the integral of the given $f$ is zero no matter how you define $0 \cdot \infty$. Adopting that convention just means that you can write a more compact expression for the integral of $f = c \cdot 1_A$, one which doesn't require $c=\infty$ or $m(A)=\infty$ to be special cases. But measure theory doesn't change in any way if you use a different convention.
May 13, 2020 at 2:38 history answered Nik Weaver CC BY-SA 4.0