Skip to main content
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
added 4 characters in body
Source Link
swami
  • 375
  • 1
  • 6

Is it true that every odd prime number is a member of one or more pairs of primes $(p_1, p_2)$ such that $p_1$ and $p_2$ are inbetween and equidistant from two adjacent powers of some number $n$? i.e.

$0 < p_1 - n^m = n^{m+1} - p_2 $ for some positive integers $n, m$

For example the prime number $73$ is a member of the pair $(73, 179)$ where $73 - 6^2 = 6^3 - 179$

Is it true that every prime number is a member of one or more pairs of primes $(p_1, p_2)$ such that $p_1$ and $p_2$ are inbetween and equidistant from two adjacent powers of some number $n$? i.e.

$0 < p_1 - n^m = n^{m+1} - p_2 $ for some positive integers $n, m$

For example the prime number $73$ is a member of the pair $(73, 179)$ where $73 - 6^2 = 6^3 - 179$

Is it true that every odd prime number is a member of one or more pairs of primes $(p_1, p_2)$ such that $p_1$ and $p_2$ are inbetween and equidistant from two adjacent powers of some number $n$? i.e.

$0 < p_1 - n^m = n^{m+1} - p_2 $ for some positive integers $n, m$

For example the prime number $73$ is a member of the pair $(73, 179)$ where $73 - 6^2 = 6^3 - 179$

specified that primes should be between integer powers and incorporated @GH comment
Source Link
swami
  • 375
  • 1
  • 6

do Do prime pairs inbetween and equidistant from adjacent integer powers cover all the prime numbers?

Is it true that every prime number is a member of one or more pairs of primes $(p_1, p_2)$ such that $p_1$ and $p_2$ are inbetween and equidistant from and between two adjacent powers of some number $n$? i.e.

$p_1 - n^m = n^{m+1} - p_2 = d$$0 < p_1 - n^m = n^{m+1} - p_2 $ for some positive integers $n, m, d$$n, m$

For example the prime number $73$ is a member of the pair $(73, 179)$ where $73 - 6^2 = 6^3 - 179 = 37$$73 - 6^2 = 6^3 - 179$

do prime pairs equidistant from adjacent integer powers cover all the prime numbers

Is it true that every prime number is a member of one or more pairs of primes $(p_1, p_2)$ such that $p_1$ and $p_2$ are equidistant from and between two adjacent powers of some number $n$? i.e.

$p_1 - n^m = n^{m+1} - p_2 = d$ for some positive integers $n, m, d$

For example the prime number $73$ is a member of the pair $(73, 179)$ where $73 - 6^2 = 6^3 - 179 = 37$

Do prime pairs inbetween and equidistant from adjacent integer powers cover all the prime numbers?

Is it true that every prime number is a member of one or more pairs of primes $(p_1, p_2)$ such that $p_1$ and $p_2$ are inbetween and equidistant from two adjacent powers of some number $n$? i.e.

$0 < p_1 - n^m = n^{m+1} - p_2 $ for some positive integers $n, m$

For example the prime number $73$ is a member of the pair $(73, 179)$ where $73 - 6^2 = 6^3 - 179$

specified that primes should be between integer powers and incorporated @GH comment
Source Link
swami
  • 375
  • 1
  • 6

Is it true that every prime number is a member of one or more pairs of primes $(p_1, p_2)$ such that $p_1$ and $p_2$ are equidistant from and between two adjacent powers of some number $n$? i.e.

$p_1 - n^m = n^{m+1} - p_2 = d$ for some positive integerintegers $d$$n, m, d$

For example the prime number $73$ is a member of the pair $(73, 179)$ where $73 - 6^2 = 6^3 - 179 = 37$

Is it true that every prime number is a member of one or more pairs of primes $(p_1, p_2)$ such that $p_1$ and $p_2$ are equidistant and between two adjacent powers of some number $n$? i.e.

$p_1 - n^m = n^{m+1} - p_2 = d$ for some positive integer $d$

For example the prime number $73$ is a member of the pair $(73, 179)$ where $73 - 6^2 = 6^3 - 179 = 37$

Is it true that every prime number is a member of one or more pairs of primes $(p_1, p_2)$ such that $p_1$ and $p_2$ are equidistant from and between two adjacent powers of some number $n$? i.e.

$p_1 - n^m = n^{m+1} - p_2 = d$ for some positive integers $n, m, d$

For example the prime number $73$ is a member of the pair $(73, 179)$ where $73 - 6^2 = 6^3 - 179 = 37$

specified that primes should be between integer powers and incorporated @GH comment
Source Link
swami
  • 375
  • 1
  • 6
Loading
Source Link
swami
  • 375
  • 1
  • 6
Loading