Timeline for Does Weyl's Inequality prove equidistribution?
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Mar 26 at 15:24 | history | suggested | The Amplitwist | CC BY-SA 4.0 |
fixed broken MathJax (there was an extra backslash); added link to David's comment
|
| Mar 26 at 12:11 | review | Suggested edits | |||
| S Mar 26 at 15:24 | |||||
| Aug 23, 2010 at 21:37 | history | edited | George Lowther | CC BY-SA 2.5 |
simplified
|
| Aug 18, 2010 at 19:26 | comment | added | George Lowther | f your other question is to ask if the sums $\sum_ncos(2\pi\theta n^k)/n$ and/or $\sum_nsin(2\pi\theta n^k)/n$ converge for irrational $\theta$, I think I know the answer to that one... | |
| Aug 18, 2010 at 18:51 | comment | added | David E Speyer | OK, this works. Nice. I should probably ask another question at some point... | |
| Aug 18, 2010 at 17:27 | comment | added | George Lowther | About Gauss sums with composite denominators: looks like they are just products of Gauss sums with prime (or prime power) denominators! I edited my answer again, and hopefully it holds together now. | |
| Aug 18, 2010 at 17:25 | history | edited | George Lowther | CC BY-SA 2.5 |
added 573 characters in body
|
| Aug 18, 2010 at 16:53 | comment | added | George Lowther | In fact, I think (3) can be fixed by requiring that there are no solutions to $x^2+1=0$ (mod b). Then you can show that $S_b$ is not fixed by the element of the Galois group taking u to 1/u. I'm going to come back to this. | |
| Aug 18, 2010 at 16:44 | comment | added | George Lowther | I tried to fix it, but it just shifted the error to the proof of (3). I'm hopeful it can still be fixed though. | |
| Aug 18, 2010 at 16:42 | history | edited | George Lowther | CC BY-SA 2.5 |
added 206 characters in body
|
| Aug 18, 2010 at 16:35 | comment | added | David E Speyer | Interesting. I hope you can fix this. Note that, when $p$ is prime, $\sum_{k=0}^{p-1} e^{2 \pi i k^2/p}$ is a Gauss sum, and is known to have norm $\sqrt{p}$. People probably know the values of Gauss sums for composite denominators, although I don't. | |
| Aug 18, 2010 at 16:32 | history | edited | George Lowther | CC BY-SA 2.5 |
fixed error in proof
|
| Aug 18, 2010 at 16:01 | history | edited | George Lowther | CC BY-SA 2.5 |
fix typos; added 258 characters in body
|
| Aug 18, 2010 at 15:50 | history | answered | George Lowther | CC BY-SA 2.5 |