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May 7, 2020 at 6:17 comment added Oeyvind Solberg If you apply the duality to $\operatorname{Tr}\Omega^{n-2}(M)$, then you get the $(n-1)$-Auslander-Reiten translation of $M$ (see sciencedirect.com/science/article/pii/S0001870806001721).
May 6, 2020 at 15:50 comment added Mare @JeremyRickard Thanks, one can find that in their book. I would hope that somewhere in the literature there has appeared an official name for that and not just a symbol. (maybe in the theory of general noetherian rings, which I do not follow very closely)
May 6, 2020 at 14:20 comment added Jeremy Rickard You probably already know that the cokernel of $P_{n-2}^{*} \rightarrow P_{n-1}^{*}$ is $\text{Tr }\Omega^{n-2}M$. I don't know a name, but Auslander and Bridger gave it a symbol, $J_{n-2}M$.
May 6, 2020 at 11:49 comment added Pedro Ah! I see. Thanks! :)
May 6, 2020 at 11:39 comment added Mare @PedroTamaroff I think Tr is called Auslander-Bridger transpose (which exists for any noetherian ring) while $\tau$=DTr is called Auslander-Reiten translate for Artin algebras.
May 6, 2020 at 11:37 comment added Pedro Isn't your $\mathrm{Tr}(M)$ what people call the Auslander--Reiten transpose? Or am I missing something? (Perhaps just different nomenclature?)
May 6, 2020 at 11:26 history edited Mare CC BY-SA 4.0
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May 6, 2020 at 10:47 history asked Mare CC BY-SA 4.0