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Aug 26, 2010 at 13:09 comment added Benoît Kloeckner I have turned this into a tricky article, see tricki.org/article/…
Aug 18, 2010 at 11:18 vote accept David E Speyer
Aug 18, 2010 at 11:18 vote accept David E Speyer
Aug 18, 2010 at 11:18
Aug 18, 2010 at 11:17 comment added David E Speyer That's really slick! Now to think about whether I can push it to handle the math.SE question...
Aug 18, 2010 at 10:30 comment added George Lowther Sorry, wasn't very clear there. I meant, for each N it uniformly bounds $\{S^t_N\colon t\in\mathbb{R}\}$.
Aug 18, 2010 at 10:24 comment added George Lowther +1 fantastic! This looks good to me. Weyl's inequality only refers to the degree of f and its leading coefficient, which are the same for all translates of f. So it uniformly bounds all $S^t_N$.
Aug 18, 2010 at 9:35 history answered Benoît Kloeckner CC BY-SA 2.5