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S May 14, 2020 at 19:03 history bounty ended CommunityBot
S May 14, 2020 at 19:03 history notice removed CommunityBot
S May 6, 2020 at 17:51 history bounty started CommunityBot
S May 6, 2020 at 17:51 history notice added user131113 Authoritative reference needed
May 4, 2020 at 19:40 comment added user131113 @JohnGreenwood ok, I see. But the question is not about taking polynomial generators for whole $\pi_*(MU)$. I just want to take some of them (with the required property) and after that take their Hurewicz images as the missing part of polynomial generators of $H_*(MU)$. Actually, I'm wondering if there a nice description of $H_*(MSU; \mathbb F_p)$ as an $\mathfrak A_p$ comodule
May 4, 2020 at 17:51 comment added John Greenwood Well if $p=3$ for example then you're only allowing polynomial generators of degree 2,6,8,10.... Since you're missing a generator of degree 4, you'll miss one of the two copies of $\mathbb{Z}$ in $\pi_4MU$.
May 4, 2020 at 17:41 comment added user131113 @JohnGreenwood yes, $M_n$ are supposed to be polynomial generators of $\pi_*(MU)$, but $M_n$ is $2n$-dimensional, so they should be polynomial generators of degree $2n \neq 2(p^t-1)$. What kind of problems could appear there?
May 4, 2020 at 16:25 comment added John Greenwood Are the $M_n$ supposed to be polynomial generators of $\pi_*MU$? If so, it seems like the degree restriction $n\neq p^t-1$ will cause problems.
May 4, 2020 at 0:58 history asked user131113 CC BY-SA 4.0