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May 2, 2020 at 1:15 comment added Tony419 Paata, thanks so much! :]
May 1, 2020 at 23:50 comment added Paata Ivanishvili Take $f(x) = \int_{-\infty}^{x} e^{-t^{2}}dt \in L^{\infty}$. Now its square function is $+\infty$.
May 1, 2020 at 22:17 review First posts
May 1, 2020 at 22:46
May 1, 2020 at 22:07 history asked Tony419 CC BY-SA 4.0