Timeline for Does Weyl's Inequality prove equidistribution?
Current License: CC BY-SA 2.5
8 events
| when toggle format | what | by | license | comment | |
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| Aug 18, 2010 at 11:36 | comment | added | George Lowther | ok, I edited my answer accordingly, and to refer to Benoît's answer. | |
| Aug 18, 2010 at 11:33 | history | edited | George Lowther | CC BY-SA 2.5 |
edited in light of Benoit's answer
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| Aug 17, 2010 at 22:58 | history | edited | George Lowther | CC BY-SA 2.5 |
oops, point out the flaw
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| Aug 17, 2010 at 22:54 | comment | added | David E Speyer | I definitely agree that this shows lim inf S_N/N=0. | |
| Aug 17, 2010 at 22:42 | history | edited | George Lowther | CC BY-SA 2.5 |
added 83 characters in body
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| Aug 17, 2010 at 22:39 | comment | added | George Lowther | You can find arbitrarily large q's satisfying $\vert\theta-p/q\vert\le1/q^2$. As p/q tends to $\theta$ for large q, even after canceling to get p/q in lowest terms, there will be infinitely many distinct q's. So, certainly, you can find p/q in lowest terms with q exceeding the bound $N_0$. | |
| Aug 17, 2010 at 22:36 | comment | added | David E Speyer | But there has to be $p$, with $GCD(p,q)=1$, such that $|\theta - p/q| < 1/q^2$. How do you guarantee that for your choice of $q$'s? | |
| Aug 17, 2010 at 22:33 | history | answered | George Lowther | CC BY-SA 2.5 |