Timeline for Acting with all rational rotations on a subset of the circle having positive measure do you fill almost the whole circle?
Current License: CC BY-SA 4.0
7 events
when toggle format | what | by | license | comment | |
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Apr 27, 2020 at 15:23 | answer | added | Claudio Rea | timeline score: 0 | |
Apr 26, 2020 at 2:13 | comment | added | jcdornano | By the aswer of Nik Weaver we have the same result for any infinite $\Gamma$. | |
Apr 25, 2020 at 22:21 | history | became hot network question | |||
Apr 25, 2020 at 16:37 | answer | added | Nik Weaver | timeline score: 14 | |
Apr 25, 2020 at 14:56 | answer | added | Josiah Park | timeline score: 6 | |
Apr 25, 2020 at 14:45 | comment | added | Gerhard Paseman | If there is a counterexample, E can be taken to be a union of orbits of Gamma without being of full measure. I think one can show a la Vitali that such an E is non-measurable, but I am unsure. If not, consider Bernstein sets. Gerhard "Taking Measure Of This Question" Paseman, 2020.04.25. | |
Apr 25, 2020 at 14:12 | history | asked | Claudio Rea | CC BY-SA 4.0 |