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Apr 25, 2020 at 5:06 vote accept Anton Sorokovskiy
Apr 24, 2020 at 22:23 comment added LSpice Oh, I was, and perhaps @AnthonyQuas was also, assuming that $f$ was non-negative.
Apr 24, 2020 at 20:54 answer added Bruno Le Floch timeline score: 6
Apr 24, 2020 at 19:54 comment added Anton Sorokovskiy @LSpice, could you help me to get this inequality?
S Apr 24, 2020 at 19:30 history edited LSpice CC BY-SA 4.0
Minor Math Jaxing, formatting and grammar.
S Apr 24, 2020 at 19:30 history suggested Daniele Tampieri CC BY-SA 4.0
Minor Math Jaxing, formatting and grammar.
Apr 24, 2020 at 19:28 comment added Anton Sorokovskiy @LSpice, I thought about it, but what if g can be negative on part of its support?
Apr 24, 2020 at 19:25 review Close votes
Apr 26, 2020 at 16:47
Apr 24, 2020 at 19:09 comment added LSpice @AntonSorokovskiy, you'll get something greater than $g(x) = \min g$, unless $E = \mathbb R$ (where I assume all this lives). This is not research level.
Apr 24, 2020 at 19:09 review Suggested edits
S Apr 24, 2020 at 19:30
Apr 24, 2020 at 18:59 comment added Anton Sorokovskiy @Anthony Quas, could you add some details? What should I get if I write f*g(x)?
Apr 24, 2020 at 18:53 comment added Anthony Quas If the global minimum for $g$ occurs on a set $E$, then write out $f\star g(x)$ for $x\in E$.
Apr 24, 2020 at 18:46 history asked Anton Sorokovskiy CC BY-SA 4.0