Timeline for Distribution of the individual coordinates of a uniform random vector on a high-dimensional sphere
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Jun 5, 2022 at 19:44 | comment | added | dohmatob | Yes, by rotational invariance. | |
| Jun 5, 2022 at 14:03 | comment | added | lazyleo | Does that mean $P(\vert U^\top z\vert>\delta) = P(\vert U_1\vert>\delta\Vert z\Vert) $? | |
| Jun 5, 2022 at 13:49 | history | edited | dohmatob | CC BY-SA 4.0 |
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| Jun 5, 2022 at 13:47 | comment | added | dohmatob | Well, precisely because $\|z\| = 1$ as in the theorem. I've made this more explicit. | |
| Jun 5, 2022 at 13:09 | comment | added | lazyleo | I am confused that why does the equation (2) is independent of $norm(z)$. | |
| Apr 20, 2020 at 6:57 | history | edited | dohmatob | CC BY-SA 4.0 |
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| Apr 19, 2020 at 17:20 | history | answered | dohmatob | CC BY-SA 4.0 |