Timeline for Minimum area of the convex hull of the union of a parallelogram and a triangle
Current License: CC BY-SA 4.0
17 events
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| Apr 15, 2020 at 15:06 | answer | added | user44143 | timeline score: 2 | |
| Apr 13, 2020 at 2:36 | history | edited | Wlodek Kuperberg | CC BY-SA 4.0 |
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| Apr 13, 2020 at 0:30 | history | edited | Wlodek Kuperberg | CC BY-SA 4.0 |
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| Apr 13, 2020 at 0:17 | history | edited | Wlodek Kuperberg | CC BY-SA 4.0 |
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| Apr 11, 2020 at 21:22 | history | edited | Wlodek Kuperberg | CC BY-SA 4.0 |
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| Apr 11, 2020 at 21:15 | history | edited | Wlodek Kuperberg | CC BY-SA 4.0 |
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| Apr 11, 2020 at 20:58 | comment | added | Wlodek Kuperberg | @YaakovBaruch: Yes, and more. I am about to show a drawing | |
| Apr 11, 2020 at 20:43 | comment | added | Yaakov Baruch | A $\sqrt{2}$ example is also achieved by a unit a square and an isosceles triangle of base and height $\sqrt{2}$, with the base centered on that of the square. | |
| Apr 11, 2020 at 16:32 | comment | added | user44143 | One way I see to make this more tractable is to show that, if the unit square is $\{\pm\frac12, \pm\frac12\}$, then up to rotations there must be one triangle corner each with $x\le-\frac12, y\ge-\frac12;$ and with $x\ge-\frac12,y\ge\frac12;$ and with $x\ge\frac12, y\le\frac12$. | |
| Apr 10, 2020 at 16:05 | comment | added | Wlodek Kuperberg | @JosephO'Rourke: done. | |
| Apr 10, 2020 at 15:52 | history | edited | Wlodek Kuperberg | CC BY-SA 4.0 |
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| Apr 10, 2020 at 11:56 | comment | added | Joseph O'Rourke | Could you describe your $\sqrt{2}$ example? | |
| Apr 10, 2020 at 11:29 | history | edited | YCor |
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| Apr 10, 2020 at 11:20 | comment | added | Yaakov Baruch | Would be interesting to know if the minimum area solutions coincide with the minimum perimeter ones... Any guess there? | |
| Apr 10, 2020 at 11:14 | comment | added | Yaakov Baruch | are the triangle and parallelogram variables in the question, or given? | |
| Apr 10, 2020 at 10:57 | history | edited | user44143 |
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| Apr 10, 2020 at 3:01 | history | asked | Wlodek Kuperberg | CC BY-SA 4.0 |