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when toggle format what by license comment
Apr 9, 2020 at 23:31 comment added Joe Silverman @Wojowu Thanks.I fixed it. I'm used to writing it as $|n| \le \text{Disc}^{2+\epsilon}$, since the upper bound for $n$ is the way it usually used in applications.
Apr 9, 2020 at 23:29 history edited Joe Silverman CC BY-SA 4.0
Fixed typo
Apr 9, 2020 at 21:06 comment added Wojowu Shouldn't the strong conjecture have $1-\epsilon$ in the exponent?
Apr 9, 2020 at 20:47 history answered Joe Silverman CC BY-SA 4.0