Timeline for Equation of the Chebyshev $\psi$ function
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
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| S Apr 8, 2020 at 18:09 | history | suggested | KhashF | CC BY-SA 4.0 |
The definition of the Chebyshev function is modified, the inequality defining the bounds of the summation is not strict.
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| Apr 8, 2020 at 17:31 | review | Suggested edits | |||
| S Apr 8, 2020 at 18:09 | |||||
| Apr 8, 2020 at 16:56 | vote | accept | Aster Phoenix | ||
| Apr 8, 2020 at 16:47 | answer | added | KhashF | timeline score: 5 | |
| S Apr 7, 2020 at 23:56 | history | edited | Amir Sagiv | CC BY-SA 4.0 |
\edit equation formula + English
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| S Apr 7, 2020 at 23:56 | history | suggested | zeraoulia rafik | CC BY-SA 4.0 |
\edit equation formula
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| Apr 7, 2020 at 21:51 | review | Suggested edits | |||
| S Apr 7, 2020 at 23:56 | |||||
| Apr 7, 2020 at 19:05 | history | edited | Aster Phoenix | CC BY-SA 4.0 |
added 1 character in body
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| Apr 7, 2020 at 12:05 | comment | added | Aster Phoenix | So if we find this bound that mean when take a n and A greater than this bound the equation E does not has integers solution | |
| Apr 7, 2020 at 11:57 | comment | added | Wojowu | Exact bound on how large $n$ has to be so that $n! > 2(A+2)$, so that Bertrans can be applied. | |
| Apr 7, 2020 at 11:50 | comment | added | Aster Phoenix | Exact bound of what can you explain more | |
| Apr 7, 2020 at 11:40 | comment | added | Wojowu | Taking exponentials, we get $l(n!)=l(A)l(A+2)$, where $l(x)$ is the least common multiple of all natural numbers below $x$. We have $A\approx n!/2$, so there will be a prime $p$ between $A+2$ and $n!$ by Bertrand for large $n$. But then $p\mid l(n!)$ and $p\nmid l(A)l(A+2)$. If anyone feels like writing up the exact bounds, feel free to turn this into an answer. | |
| Apr 7, 2020 at 10:48 | history | asked | Aster Phoenix | CC BY-SA 4.0 |