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Apr 7, 2020 at 9:55 review Close votes
Apr 14, 2020 at 3:05
Apr 6, 2020 at 13:07 comment added Gerald Edgar Any random variable $\xi$ ? No. Any random variable $\xi$ as specified in Theorem 1.3. If $\xi \in L^2$, then it hods for $C_0=2$ by definition of $L^2$. Presumably the random variables in Theorem 1.3 need not be in $L^2$, so he has to use a larger constant $C_0$. Perhaps they state it that way because they do not actually compute the constant $C_0$ that works, they only prove that one exists.
Apr 6, 2020 at 12:41 vote accept ABIM
Apr 6, 2020 at 12:35 comment added YCor "Absolute constant" usually means it does not depend on any of the fixed data.
Apr 6, 2020 at 12:34 answer added Alexandre Eremenko timeline score: 6
Apr 6, 2020 at 12:34 history edited YCor CC BY-SA 4.0
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Apr 6, 2020 at 11:46 comment added ABIM So it holds for any $\xi$ random variables in $L^2$?
Apr 6, 2020 at 11:41 history edited GH from MO
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Apr 6, 2020 at 11:20 history asked ABIM CC BY-SA 4.0