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Apr 25, 2020 at 17:33 history edited Sharik
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Apr 10, 2020 at 11:47 vote accept Sharik
Apr 10, 2020 at 11:44 comment added Igor Khavkine I should have written "...applying the Euler-Lagrange operator to both sides...". The Euler-Lagrange operator starts off a sequence, in the same way that the exterior derivative starts off the de Rham sequence, where the Helmholtz operator is next in the sequence.
Apr 6, 2020 at 14:36 comment added Igor Khavkine @BenMcKay Every conserved current is equivalent to one s.t. its conservation condition takes the form $\mathrm{d} j[\phi] = \xi \cdot E[\phi]$ (no derivatives of the equations $E[\phi]=0$). Applying the Helmhotz operator to both sizes gives $H(\xi \cdot E[\phi])=0$, implying differential conditions on $\xi$. On appropriate equivalence classes, $j \leftrightarrow \xi$ is a bijection. When $E[\phi]=0$ is variational, the condition on $\xi$ is the same as being a symmetry of the Lagrangian.
Apr 6, 2020 at 13:55 comment added Ben McKay This theorem is known to hold for variational problems in very broad generality, but I don't think there is a theorem of this type for nonvariational problems in any generality.
Apr 6, 2020 at 13:17 answer added Igor Khavkine timeline score: 9
Apr 6, 2020 at 0:00 comment added LSpice I don't know if it'll help to answer your specific question, but I hope you won't mind my taking the excuse to share Baez's exposition Noether's theorem in a nutshell, which I've always found second to none on this subject.
Apr 5, 2020 at 23:21 comment added Michael Engelhardt Time-translation invariance implies the conservation of energy.
Apr 5, 2020 at 23:12 answer added Tom Price timeline score: 1
Apr 3, 2020 at 22:05 comment added Jonny Evans Conceptually, Noether's theorem is saying that a 1-parameter family of diffeomorphisms of the space F of fields induces a Hamiltonian flow on T^*F, and the Hamiltonian (Noether charge) is then conserved under that flow. I wrote a blog post about this a couple of years ago: jde27.uk/blog/noether.html - in particular the conservation of field momentum associated with space translation is worked out. Admittedly, I find it easier to think about going from the conserved quantity to the symmetry (from Hamiltonian to its flow) but that's just because differentiating is easier than integrating.
Apr 3, 2020 at 21:24 answer added Carlo Beenakker timeline score: 3
Apr 3, 2020 at 21:07 comment added Willie Wong The equation you wrote is variational. So you can use the general formalism there to make the computation starting from an appropriate Lagrangian. (Here the action is $$-u_t^2 + u_x^2 + F(u)$$ where $F$ is an antiderivative of the scalar function $f$.) Following en.wikipedia.org/wiki/Noether%27s_theorem#Field_theory_version you can get a conserved current $j$. Integrating $j^0$ along $\{t = const\}$ gives you the time-independent conserved quantity.
Apr 3, 2020 at 20:54 history asked Sharik CC BY-SA 4.0