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Bugs Bunny
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Read about Frobenius-Schur anywhere. In a nutshell a complex irreducible $V$ of complex dimension $n$ can give 1 or 2 real irreducibles, whose real dimensions are $n$ or $n/2$$2n$. This can be easily determined by computing the FS-indicator or dimensions of invariants in both $S^2V$ and $\Lambda^2 V$. The latter can be done in Lie for each particular representation.

Read about Frobenius-Schur anywhere. In a nutshell a complex irreducible $V$ of complex dimension $n$ can give 1 or 2 real irreducibles, whose real dimensions are $n$ or $n/2$. This can be easily determined by computing the FS-indicator or dimensions of invariants in both $S^2V$ and $\Lambda^2 V$. The latter can be done in Lie for each particular representation.

Read about Frobenius-Schur anywhere. In a nutshell a complex irreducible $V$ of complex dimension $n$ can give 1 or 2 real irreducibles, whose real dimensions are $n$ or $2n$. This can be easily determined by computing the FS-indicator or dimensions of invariants in both $S^2V$ and $\Lambda^2 V$. The latter can be done in Lie for each particular representation.

Source Link
Bugs Bunny
  • 12.3k
  • 1
  • 30
  • 65

Read about Frobenius-Schur anywhere. In a nutshell a complex irreducible $V$ of complex dimension $n$ can give 1 or 2 real irreducibles, whose real dimensions are $n$ or $n/2$. This can be easily determined by computing the FS-indicator or dimensions of invariants in both $S^2V$ and $\Lambda^2 V$. The latter can be done in Lie for each particular representation.