Timeline for Estimate for $\sum_{a=1}^{p-1}\sum_{b=1}^{p-1}\frac{b}{a(ab)_p}$, where $p$ is a large prime

14 events

when toggle format	what		by	license	comment
Mar 31, 2020 at 8:46	history	edited	Sylvain JULIEN	CC BY-SA 4.0	added 159 characters in body
Mar 30, 2020 at 22:46	history	edited	Sylvain JULIEN	CC BY-SA 4.0	added 2 characters in body
Mar 30, 2020 at 21:11	history	edited	Sylvain JULIEN	CC BY-SA 4.0	added 208 characters in body
Mar 30, 2020 at 20:34	comment	added	GH from MO		Yes, obviously. Anyways, I don't want to chat about this, but you need to be careful.
Mar 30, 2020 at 20:30	comment	added	Sylvain JULIEN		It would be the same if the sum over $b$ went from $1$ to $a$, right?
Mar 30, 2020 at 20:26	comment	added	GH from MO		No, a different argument is needed. Your first display talks about a very different sum than the original post.
Mar 30, 2020 at 19:56	comment	added	Sylvain JULIEN		So a multiplicative factor equal $2$ is needed?
Mar 30, 2020 at 19:23	comment	added	GH from MO		Your first display only covers the pairs $(a,b)$ satisfying $b\leq a$ (since your $d^2/n$ equals $b/a$).
Mar 30, 2020 at 18:52	history	edited	Sylvain JULIEN	CC BY-SA 4.0	added 112 characters in body
Mar 30, 2020 at 18:52	comment	added	Steven Stadnicki		Can you get a lower bound this way, too?
Mar 30, 2020 at 17:42	history	edited	Sylvain JULIEN	CC BY-SA 4.0	added 7 characters in body
Mar 30, 2020 at 17:32	history	edited	Sylvain JULIEN	CC BY-SA 4.0	deleted 84 characters in body
Mar 30, 2020 at 17:23	history	edited	Sylvain JULIEN	CC BY-SA 4.0	added 1 character in body
Mar 30, 2020 at 17:18	history	answered	Sylvain JULIEN	CC BY-SA 4.0