Timeline for Estimate for $\sum_{a=1}^{p-1}\sum_{b=1}^{p-1}\frac{b}{a(ab)_p}$, where $p$ is a large prime
Current License: CC BY-SA 4.0
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Mar 30, 2020 at 21:58 | comment | added | Gerry Myerson | Just to be clear, this isn't the sum, it's the sum divided by $p(\log p)^2$. | |
Mar 30, 2020 at 15:56 | history | answered | Neil Strickland | CC BY-SA 4.0 |