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Mar 29, 2020 at 14:38 vote accept RayyyyySun
Mar 27, 2020 at 16:20 comment added RayyyyySun I see, Thanks! really appreciate :)
Mar 27, 2020 at 16:19 comment added M. Winter @RayyyyySun Not with every matrix, just with those for which $(1,...,1)$ is an eigenvector, and all other eigenvectors are perpendicular to $(1,...,1)$.
Mar 27, 2020 at 16:17 comment added RayyyyySun Thanks! So the key is J ,in general, has a common set of eigenvectors with any matrix, right?
Mar 27, 2020 at 16:14 history edited M. Winter CC BY-SA 4.0
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Mar 27, 2020 at 16:09 history answered M. Winter CC BY-SA 4.0