Timeline for Blocking set in a projective plane.
Current License: CC BY-SA 2.5
9 events
| when toggle format | what | by | license | comment | |
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| Aug 19, 2010 at 11:11 | comment | added | damiano | The case $q=2$ requires a little extra care, but is not difficult. The reason the above argument does not apply is that triangles contain lines in the case $q=2$. | |
| Aug 14, 2010 at 23:13 | history | edited | damiano | CC BY-SA 2.5 |
added 136 characters in body; deleted 18 characters in body
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| Aug 14, 2010 at 23:05 | history | edited | damiano | CC BY-SA 2.5 |
added 14 characters in body
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| Aug 14, 2010 at 22:52 | comment | added | damiano | The version above is completely different and should answer the full question. | |
| Aug 14, 2010 at 22:51 | history | edited | damiano | CC BY-SA 2.5 |
completely revised, now should be a full proof
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| Aug 14, 2010 at 19:30 | comment | added | jeff | Looks nice, although i'm not sure why you are using a conics in your proof, Can't you just define a set of points in the projective plane? BTW, is it possible to conclude from this about equality? thanks. | |
| Aug 14, 2010 at 19:29 | vote | accept | jeff | ||
| Aug 14, 2010 at 16:06 | history | edited | damiano | CC BY-SA 2.5 |
added 41 characters in body
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| Aug 14, 2010 at 16:00 | history | answered | damiano | CC BY-SA 2.5 |