Timeline for Does there exist a rational polynomial $P(x)\in{\mathbb Q}[x]{}$ such that $P(\zeta(s))=\zeta(P(s))$?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Mar 26, 2020 at 10:04 | history | edited | Wojowu | CC BY-SA 4.0 |
woops, mixed it up with Gamma function
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| Mar 25, 2020 at 23:20 | comment | added | GH from MO | @SylvainJULIEN: There is a simple proof for all complex polynomials. See my post below. | |
| Mar 25, 2020 at 23:11 | comment | added | Sylvain JULIEN | Doesn't your argument also apply for polynomials in $\mathbb{R}[x]$? | |
| Mar 25, 2020 at 23:00 | history | answered | Wojowu | CC BY-SA 4.0 |