Some cobordism invariants are not cohomology classes. Such as the $\mathbb{Z}_{16}$-valued eta invariant $\eta$ of $\Omega_4^{Pin^+}$, the $\mathbb{Z}_8$-valued Arf-Brown-Kervaire invariant ABK of $\Omega_2^{Pin^-}$, and the $\mathbb{Z}_4$-valued quadratic enhancement $q(a)$ of $\Omega_2^{Pin^-}(B\mathbb{Z}_2)$ where $a\in H^1(M,\mathbb{Z}_2)$. The last invariant is defined as follows: Any 2-manifold $M$ always admits a $Pin^-$ structure. $Pin^-$ structures are in one-to-one correspondence with quadratic enhancements $$q: H^1(M,\mathbb{Z}_2)\to\mathbb{Z}_4$$ such that $$q(x+y)-q(x)-q(y)=2\int_M x\cup y\mod4.$$ In particular, $$q(x)=\int_M x\cup x\mod2.$$ There are many more such examples, I only mention these.
By this question, the etaWe say that a cobordism invariant $\eta$ is not a topological invariant butif it can be defined purely using topological data, for example, if it is a cohomology class. While we say that a cobordism invariant is geometric if it can be defined purely using geometric data like metric, connection, and curvature.
These two definitions have no confliction, a cobordism invariant can be both topological and geometric.
My question: AreDetermine whether the other two cobordism invariants mentioned above are topological orand geometric?. In general, how to determine whether aare there any examples of cobordism invariant isinvariants which are geometric but not topological or? Are there any examples of cobordism invariants which are topological but not geometric?
For example, the eta invariant $\eta$ is discussed in this question.
Thank you!