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Feb 27, 2010 at 1:53 comment added Gerald Edgar $\mathbb{C}(X)$ embeds into $\mathbb{C}$ ... but is the Axiom of Choice required to prove it?
Feb 26, 2010 at 19:38 comment added LSpice John, one of my favourite applications of this is that $\mathbb C(X)$ embeds into $\mathbb C$. A great true/false question for an algebra exam!
Nov 1, 2009 at 14:56 comment added Peter Arndt Wow, that matroid point of view is very nice - I had never heard of someone thinking about it like that
Oct 31, 2009 at 19:50 comment added John Goodrick Really, "no geometry"? I realize this is very subjective, but the idea of proving that algebraically closed fields have a matroid structure feels very "geometric" to me, since it reminds me of the canonical matroids that arise from projective and affine spaces.
Oct 31, 2009 at 16:48 comment added Ben Webster John, the reason model theorists like this result and geometers don't is that there's no geometry in it. Well, that and it's wildly non-canonical.
Oct 31, 2009 at 16:03 comment added Harrison Brown It's a good point, and I've seen the result, but I really only need one example... :)
Oct 31, 2009 at 15:44 history answered John Goodrick CC BY-SA 2.5