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Sep 12, 2010 at 2:34 vote accept David Spivak
Sep 12, 2010 at 0:25 answer added Todd Trimble timeline score: 7
Sep 2, 2010 at 22:32 comment added some guy on the street edit: "the as" $\mapsto$ "as the"
Sep 2, 2010 at 22:31 comment added some guy on the street After stewing on the implicit puzzle, I have to admit I don't see how to get down to three factors. Can you tell me if I seem to understand left/right pushouts well-enough if I say I'm using the as definition of Image "a coequalizer of a kernel pair"? As a bonus, you practically get the requested epic/monic factorization for free; but I think there are at least three extra pull-backs in my recipe.
Aug 16, 2010 at 21:47 comment added some guy on the street Since there are three factors, I wonder if someone did/should check whether there's a prop/struct/stuff factorization (aka. Postnikov-Moore!) lurking about?
Aug 14, 2010 at 6:16 comment added Peter LeFanu Lumsdaine Some very vague scraps of memory that might be relevant: polynomial functors can be seen as an internal cousin of familially representable functors. Fam. rep. functors have a nice characterisation as “preserving wide pullbacks” (Carboni/Johnstone). Iirc, there are some nice constructions making the analogy between poly. and fam. rep. functors concrete, and iirc there may have been an internal analogue of the “wide pullbacks” condition. Unfortunately I can't remember the details, or even where/from whom I heard this. I think they said it was from work by Joyal, perhaps?
Aug 13, 2010 at 21:32 comment added Andrew Stacey +1 for the title alone!
Aug 13, 2010 at 19:37 history asked David Spivak CC BY-SA 2.5